Засварлах: ᠱᠦᠯᠲᠦ (хэсэгчилэн)

=ᠬᠢᠮᠢ ᠶ᠋ᠢᠨ ᠰᠢᠨᠵᠢ ᠴᠢᠨᠠᠷ=
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|text=ᠱᠦᠯᠲᠦ ᠬᠡᠮᠵᠢᠭᠦᠷ
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ᠱᠦᠯᠲᠦ ᠨᠤᠭᠦᠳ ᠰᠠᠭᠤᠷᠢ ᠶ᠋ᠢᠨ ᠰᠢᠨᠵᠢ ᠴᠢᠨᠠᠷ ‍ᠢ ᠦᠵᠡᠭᠦᠯᠳᠡᠭ᠃ 
ᠬᠠᠲᠠᠭᠤ ᠲᠥᠯᠦᠪ ᠲᠦ ᠪᠠᠢᠢᠬᠤ ᠳ᠋ᠤ ᠪᠠᠨ ᠪᠦᠬᠦ ᠱᠦᠯᠲᠦ ᠠᠭᠠᠷ ᠡᠴᠡ ᠤᠰᠤ ᠰᠢᠩᠭᠡᠭᠡᠬᠦ ᠪᠠ ᠲᠡᠷᠡ ᠴᠦ ᠪᠠᠢᠢᠲᠤᠭᠠᠢ ᠨᠣᠭᠦᠷᠡᠰᠦ ᠬᠦᠴᠢᠯ ᠰᠢᠩᠭᠡᠭᠡᠵᠦ᠂ ᠠᠭᠠᠵᠢᠮ ᠶ᠋ᠢᠠᠷ ᠻᠠᠷᠪᠣᠨᠠᠲ<sup>carbonate</sup> ᠲᠤ ᠤᠷᠪᠠᠳᠠᠭ᠃
ᠠᠵᠤ ᠦᠢᠯᠡᠳᠪᠦᠷᠢ ᠳ᠋ᠦ ᠱᠦᠯᠲᠦ ᠶ᠋ᠢ ᠥᠷᠭᠡᠨ ᠬᠡᠷᠡᠭᠯᠡᠳᠡᠭ᠃
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==ᠬᠦᠴᠢᠯ ᠲᠡᠢ ᠤᠷᠪᠠᠯᠳᠤᠬᠤ ᠨᠢ==
ᠱᠦᠯᠲᠦ ᠨᠤᠭᠦᠳ ᠠᠯᠢᠪᠠ ᠰᠠᠭᠤᠷᠢ ᠶ᠋ᠢᠨ ᠠᠳᠠᠯᠢ ᠬᠦᠴᠢᠯ ᠲᠡᠢ ᠬᠠᠷᠢᠨᠴᠠᠯ ᠦᠢᠯᠡᠴᠢᠯᠡᠯᠴᠡᠵᠦ ᠳᠠᠪᠠᠰᠤ ᠬᠢᠭᠡᠳ ᠤᠰᠤ ᠡᠭᠦᠰᠬᠡᠳᠡᠭ᠂ ᠡᠭᠦᠨ ‍ᠢ ᠰᠠᠭᠠᠷᠮᠠᠭᠵᠢᠬᠤ ᠤᠷᠪᠠᠯ ᠬᠡᠮᠡᠮᠦᠢ᠃ 
ᠡᠨᠡ ᠪᠣᠯ ᠱᠦᠯᠲᠦ ᠶ᠋ᠢᠨ ᠬᠠᠮᠤᠭ ᠦ᠋ᠨ ᠴᠢᠬᠤᠯᠠ ᠬᠢᠮᠢ ᠶ᠋ᠢᠨ ᠴᠢᠨᠠᠷ ᠦ᠋ᠳ ᠦ᠋ᠨ ᠨᠢᠭᠡ ᠪᠢᠯᠡ᠃
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: '''ᠱᠦᠯᠲᠦ + ᠬᠦᠴᠢᠯ → ᠳᠠᠪᠤᠰᠤ + ᠤᠰᠤ'''
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!<math>\mathsf{NaOH + HCl \longrightarrow NaCl + H_2O};</math>
!<math>\mathsf{NaOH + HNO_3 \longrightarrow NaNO_3 + H_2O}.</math>
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==ᠬᠦᠴᠢᠯ ᠦ᠋ᠨ ᠢᠰᠦᠯ ᠲᠡᠢ ᠤᠷᠪᠠᠯᠳᠤᠬᠤ ᠨᠢ==
ᠱᠦᠯᠲᠦ ᠨᠢ ᠬᠦᠴᠢᠯ ᠦ᠋ᠨ ᠢᠰᠦᠯ ᠲᠡᠢ ᠬᠠᠷᠢᠨᠴᠠᠯ ᠦᠢᠯᠡᠴᠢᠯᠡᠯᠴᠡᠵᠦ ᠳᠠᠪᠠᠰᠤ ᠬᠢᠭᠡᠳ ᠤᠰᠤ ᠡᠭᠦᠰᠬᠡᠳᠡᠭ᠃


: '''ᠱᠦᠯᠲᠦ + ᠬᠦᠴᠢᠯ ᠦ᠋ᠨ ᠢᠰᠦᠯ → ᠳᠠᠪᠤᠰᠤ + ᠤᠰᠤ'''

:<math>\mathsf{Ca(OH)_2 + CO_2 \longrightarrow CaCO_3 \downarrow + H_2O}</math>;
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==ᠠᠮᠹᠣᠲ᠋ᠧᠷ ᠢᠰᠦᠯ ᠲᠡᠢ ᠤᠷᠪᠠᠯᠳᠤᠬᠤ ᠨᠢ==
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: <math>\mathsf{2KOH + ZnO \xrightarrow{t^oC} K_2ZnO_2 + H_2O}.</math>
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==ᠠᠮᠹᠣᠲ᠋ᠧᠷ ᠮᠧᠲ᠋ᠠᠯ ᠲᠡᠢ ᠤᠷᠪᠠᠯᠳᠤᠬᠤ ᠨᠢ==
ᠱᠦᠯᠲᠦ ᠶ᠋ᠢᠨ ᠠᠭᠤᠰᠤᠮᠠᠯ ᠨᠢ ᠠᠮᠹᠣᠲ᠋ᠧᠷ<sup>amphoteric</sup> ᠢᠰᠦᠯ ᠪᠣᠯᠤᠨ ᠠᠮᠹᠣᠲ᠋ᠧᠷ ᠾᠢᠳ᠌ᠷᠣᠻᠰᠢᠳ᠋ ᠡᠭᠦᠰᠬᠡᠭᠴᠢ ᠠᠮᠹᠣᠲ᠋ᠧᠷ ᠮᠧᠲ᠋ᠠᠯ ᠦ᠋ᠳ (Zn, Al ᠭᠡᠬᠦ ᠮᠡᠲᠦ) ᠲᠠᠢ ᠬᠠᠷᠢᠨᠴᠠᠯ ᠦᠢᠯᠡᠴᠢᠯᠡᠯᠴᠡᠳᠡᠭ᠃ 
ᠲᠡᠢᠢᠮᠦ ᠤᠷᠪᠠᠯ ᠦ᠋ᠨ ᠲᠡᠭᠰᠢᠳᠬᠡᠯ ‍ᠢ ᠳᠠᠷᠠᠭᠠᠬᠢ ᠪᠠᠢᠢᠳᠠᠯ ᠶ᠋ᠢᠠᠷ ᠬᠢᠯᠪᠠᠷᠴᠢᠯᠠᠨ ᠪᠢᠴᠢᠵᠦ ᠪᠣᠯᠤᠨ᠎ ‍ᠠ᠋᠄
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!<math>\mathsf{Zn + 2NaOH \longrightarrow Na_2ZnO_2 + H_2 \uparrow};</math>
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!<math>\mathsf{2Al + 2KOH + 2H_2O \longrightarrow 2KAlO_2 + 3H_2 \uparrow}.</math>
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ᠢᠢᠮᠦ ᠤᠷᠪᠠᠯ ᠦ᠋ᠨ ᠶᠠᠪᠤᠴᠠ ᠳ᠋ᠤ ᠳᠠᠪᠤᠰᠤᠨ ‍ᠤ ᠾᠢᠳ᠌ᠷᠣᠻᠣᠮᠫᠯᠧᠻᠰ ᠡᠭᠦᠰᠳᠡᠭ:
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!<math>\mathsf{Zn + 2NaOH + 2H_2O \longrightarrow Na_2[Zn(OH)_4] + H_2 \uparrow};</math>
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!<math>\mathsf{2Al + 2KOH + 6H_2O \longrightarrow 2K[Al(OH)_4] + 3H_2 \uparrow}.</math>
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==ᠳᠠᠪᠤᠰᠤᠨ ‍ᠤ ᠠᠭᠤᠰᠤᠮᠠᠯ ᠲᠡᠢ ᠤᠷᠪᠠᠯᠳᠤᠬᠤ ᠨᠢ==
ᠤᠰᠤᠨ ᠳ᠋ᠤ ᠦᠯᠦ ᠠᠭᠤᠰᠬᠤ ᠰᠠᠭᠤᠷᠢ᠂ ᠦᠯᠦ ᠠᠭᠤᠰᠬᠤ ᠳᠠᠪᠤᠰᠤ ᠡᠭᠦᠰᠬᠦ ᠪᠡᠷ ᠪᠣᠯ ᠱᠦᠯᠲᠦ ᠶ᠋ᠢᠨ ᠠᠭᠤᠰᠤᠮᠠᠯ ᠨᠢ ᠳᠠᠪᠤᠰᠤᠨ ‍ᠤ ᠠᠭᠤᠰᠤᠮᠠᠯ ᠲᠠᠢ ᠬᠠᠷᠢᠯᠴᠠᠨ ᠦᠢᠯᠡᠴᠢᠯᠡᠯᠴᠠᠳᠡᠭ᠃

 
: '''ᠱᠦᠯᠲᠦ ᠶ᠋ᠢᠨ ᠠᠭᠤᠰᠤᠮᠠᠯ + ᠳᠠᠪᠤᠰᠤᠨ ‍ᠤ ᠠᠭᠤᠰᠤᠮᠠᠯ → ᠰᠢᠨ᠎ ‍ᠡ᠋ ᠰᠠᠭᠤᠷᠢ + ᠰᠢᠨ᠎ ‍ᠡ᠋ ᠳᠠᠪᠤᠰᠤ'''

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!<math>\mathsf{2NaOH + CuSO_4 \longrightarrow Cu(OH)_2 \downarrow + Na_2SO_4};</math>
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!<math>\mathsf{Ba(OH)_2 + Na_2SO_4 \longrightarrow 2NaOH + BaSO_4 \downarrow}.</math>
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